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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: ` 3x^2 +3xy -17 = 7x-2y` giải hộ em với

Toán Lớp 9: 3x^2 +3xy -17 = 7x-2y
giải hộ em với

Comments ( 1 )

  1. Bạn tham khảo nhé.
    Bổ sung là x,y\inZZ nhé.
    $\\$
    3x^2+3xy-17=7x-2y
    <=>3x^2+3xy-7x+2y-17=0
    <=>3x(x+y)+2x+2y-9x-17=0
    <=>3x(x+y)+2(x+y)-9x-17=0
    <=>(x+y)(3x+2)-9x-6-11=0
    <=>(x+y)(3x+2)-3(3x+2)=11
    <=>(x+y-3)(3x+2)=11
    Vì x,y\inZZ
    =>(x+y-3) và (3x+2) \inƯ(11)\in{+-1;+-11}
    \text{TH1}
    {(x+y-3=1),(3x+2=11):}
    <=>{(x+y=4),(3x=9):}
    <=>{(y=4-x),(x=3):}
    <=>{(y=4-3),(x=3):}
    <=>{(y=1),(x=3):}(\text{Nhận})
    \text{TH2}
    {(x+y-3=-1),(3x+2=-11):}
    <=>{(x+y=2),(3x=-13):}
    <=>{(y=2-x),(x=-13/3):}(\text{Loại})
    \text{TH3}
    {(x+y-3=11),(3x+2=1):}
    <=>{(x+y=14),(3x=-1):}
    <=>{(y=14-x),(x=-1/3):}(\text{Loại})
    \text{TH4}
    {(x+y-3=-11),(3x+2=-1):}
    <=>{(x+y=-8),(3x=-3):}
    <=>{(y=-8-x),(x=-1):}
    <=>{(y=-8-(-1)),(x=-1):}
    <=>{(y=-7),(x=-1):}(\text{Nhận})
    Vậy (x;y)\in(-1;-7),(3;1)
     

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222-9+11+12:2*14+14 = ? ( )