Toán Lớp 9: x^2+2/5x^2-10x+5 : 3x+3/5x-5
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Toán Lớp 9: x^2+2/5x^2-10x+5 : 3x+3/5x-5
Comments ( 2 )
\dfrac{{{x^2} + 2}}{{5{x^2} – 10x + 5}}:\dfrac{{3x + 3}}{{5x – 5}}\\
= \dfrac{{{x^2} + 2}}{{5\left( {{x^2} – 2x + 1} \right)}}.\dfrac{{5\left( {x – 1} \right)}}{{3\left( {x + 1} \right)}}\\
= \dfrac{{{x^2} + 2}}{{5{{\left( {x – 1} \right)}^2}}}.\dfrac{{5\left( {x – 1} \right)}}{{3x + 3}}\\
= \dfrac{{{x^2} + 2}}{{\left( {3x + 3} \right).\left( {x – 1} \right)}}\\
= \dfrac{{{x^2} + 2}}{{3{x^2} – 3}}
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