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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Tính GTNN :A=a mũ 4-2a mũ 3+2a mũ 2-2a+2

Toán Lớp 8: Tính GTNN :A=a mũ 4-2a mũ 3+2a mũ 2-2a+2

Comments ( 1 )

  1. A = a^4 – 2a^3 + 2a^2 – 2a + 2
       = a^4 – 2a^3 + a^2 + a^2 – 2a + 1 + 1
      = a^2(a^2 – 2a + 1) + (a^2 – 2a + 1) + 1
    = a^2(a – 1)^2 + (a – 1)^2 + 1
    = (a^2 + 1)(a – 1)^2 + 1
    Vì a^2 + 1 > 0 ∀a
    (a – 1)^2 \ge 0 ∀a
    => (a^2 + 1)(a – 1)^2 \ge 0 ∀a
    => (a^2 + 1)(a – 1)^2 + 1 \ge 1 ∀a
    Dấu “=” xảy ra khi:
    (a^2 + 1)(a – 1)^2 = 0
    Mà a^2 \ge 0 => a^2 + 1 > 0
    => (a – 1)^2 = 0
    => a – 1=  0
    => a = 1
    Vậy A_{min} = 1 tại a = 1

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222-9+11+12:2*14+14 = ? ( )

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