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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Tính A x^2+5x+4/x^2-1=A/x^2-2x+1

Toán Lớp 8: Tính A
x^2+5x+4/x^2-1=A/x^2-2x+1

Comments ( 2 )

  1. Giải đáp:
    A=(x+4)(x-1)
    Lời giải và giải thích chi tiết:
     \frac{x^2+5x+4}{x^2-1}=\frac{A}{x^2-2x+1}
    \frac{(x^2+x)+(4x+4)}{(x-1)(x+1)}=\frac{A}{(x-1)^2}
    \frac{x(x+1)+4(x+1)}{(x-1)(x+1)}=\frac{A}{(x-1)^2}
    \frac{(x+4)(x+1)}{(x-1)(x+1)}=\frac{A}{(x-1)^2}
    ⇔(x+4)(x+1)(x-1)^2=A.(x-1)(x+1)
    =>(x+4)(x+1)(x-1)(x-1)=A.(x-1)(x+1)
    =>A=(x+4)(x-1)

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222-9+11+12:2*14+14 = ? ( )