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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Tìm x (x thuộc N* ) `16x^3-25x=0`

Toán Lớp 8: Tìm x (x thuộc N* )
16x^3-25x=0

Comments ( 2 )

  1. Giải đáp:
    $16x³-25x=0$
    $⇔ x.(16x²-25)=0$    
    $⇔ x.[(4x)²-5²]=0$
    $⇔ x.(4x-5).(4x+5)=0$
    $⇔$ \(\left[ \begin{array}{l}x=0\\4x-5=0\\4x+5=0\end{array} \right.\) $⇔$ \(\left[ \begin{array}{l}x=0\\4x=5\\4x=-5\end{array} \right.\) $⇔$ \(\left[ \begin{array}{l}x=0\\x=\dfrac{5}{4}\\x=-\dfrac{5}{4}\end{array} \right.\) 
    $Vậy$ $x=0$ $hoặc$ $x=±\dfrac{5}{4}$ $\text{(x ∈ N*)}$
     

  2. 16x^3-25x=0
    x.(16x^2-25)=0
     x.((4x)^2 – 5^2)=0
    x.(4x-5).(4x+5)=0
    Trường hợp 1: x=0
    Trường hợp 2
    4x-5=0
    4x=5
    x=5/4
    Trường hợp 3
    4x+5=0
    4x=-5
    x=-5/4
    Vì x∈N* nên x∈Ф

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222-9+11+12:2*14+14 = ? ( )