Toán Lớp 8: Tìm X: x-c/9d^2-6cd=2c/4c^2-9d^2
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Toán Lớp 8: Tìm X: x-c/9d^2-6cd=2c/4c^2-9d^2
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\dfrac{{x – c}}{{9{d^2} – 6cd}} = \dfrac{{2c}}{{4{c^2} – 9{d^2}}}\\
\Leftrightarrow \dfrac{{x – c}}{{3d\left( {3d – 2c} \right)}} = \dfrac{{2c}}{{\left( {2c – 3d} \right)\left( {2c + 3d} \right)}}\\
\Leftrightarrow \dfrac{{c – x}}{{3d\left( {2c – 3d} \right)}} = \dfrac{{2c}}{{\left( {2c – 3d} \right)\left( {2c + 3d} \right)}}\\
\Leftrightarrow \dfrac{{c – x}}{{3d}} = \dfrac{{2c}}{{2c + 3d}}\\
\Leftrightarrow c – x = \dfrac{{2c}}{{2c + 3d}}.3d\\
\Leftrightarrow c – x = \dfrac{{6cd}}{{2c + 3d}}\\
\Leftrightarrow x = c – \dfrac{{6cd}}{{2c + 3d}}\\
\Leftrightarrow x = \dfrac{{2{c^2} + 3cd – 6cd}}{{2c + 3d}}\\
\Leftrightarrow x = \dfrac{{2{c^2} – 3cd}}{{2c + 3d}}\\
Vậy\,x = \dfrac{{2{c^2} – 3cd}}{{2c + 3d}}
\end{array}$