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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Tìm x biết:3x(x-2)=1-x nhanh với

Toán Lớp 8: Tìm x biết:3x(x-2)=1-x nhanh với

Comments ( 1 )

  1. Giải đáp:
    $\left[\begin{array}{l} x=\dfrac{5+\sqrt{37}}{6}\\x=\dfrac{5-\sqrt{37}}{6}\end{array} \right..$
    Lời giải và giải thích chi tiết:
    $3x(x-2)=1-x\\ \Leftrightarrow 3x^2-6x=1-x\\ \Leftrightarrow 3x^2-5x-1=0\\ \Leftrightarrow x^2-\dfrac{5}{3}x-\dfrac{1}{3}=0\\ \Leftrightarrow x^2-2.\dfrac{5}{6}x+\dfrac{25}{36}-\dfrac{37}{36}=0\\ \Leftrightarrow \left(x-\dfrac{5}{6}\right)^2-\left(\dfrac{\sqrt{37}}{6}\right)^2=0\\ \Leftrightarrow \left(x-\dfrac{5}{6}-\dfrac{\sqrt{37}}{6}\right)\left(x-\dfrac{5}{6}+\dfrac{\sqrt{37}}{6}\right)=0\\ \Leftrightarrow \left(x-\dfrac{5+\sqrt{37}}{6}\right)\left(x-\dfrac{5-\sqrt{37}}{6}\right)=0\\ \Leftrightarrow \left[\begin{array}{l} x-\dfrac{5+\sqrt{37}}{6}=0\\x-\dfrac{5-\sqrt{37}}{6}=0\end{array} \right.\\ \Leftrightarrow \left[\begin{array}{l} x=\dfrac{5+\sqrt{37}}{6}\\x=\dfrac{5-\sqrt{37}}{6}\end{array} \right..$

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222-9+11+12:2*14+14 = ? ( )