Toán Lớp 8: tìm x biết x(x-2)+3x-6=0 helpp
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Toán Lớp 8: tìm x biết x(x-2)+3x-6=0 helpp
Comments ( 2 )
Giải đáp+Lời giải và giải thích chi tiết:
x(x-2)+3x-6=0
<=>x(x-2)+3(x-2)=0
<=>(x-2)(x+3)=0
<=>\(\left[ \begin{array}{l}x-2=0\\x+3=0\end{array} \right.\)
<=>\(\left[ \begin{array}{l}x=2\\x=-3\end{array} \right.\)
Vậy x\in{-3; 2}
$x\left(x-2\right)+3x-6=0\:$
⇒x^2+x−6=0
⇒(x−2)(x+3)=0
\(⇒\left[ \begin{array}{l}x−2=0\\x+3=0\end{array} \right.\) \(⇒\left[ \begin{array}{l}x=2\\x=−3
\end{array} \right.\)
$\text{Vậy x $\in$ (2 ; −3)}$