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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: tìm x a)15^2-3x=0 b)(3x-2)(x+3)+(x^2-9)=0 c) (x-1)^2-(x+10(2-3×0=-3

Toán Lớp 8: tìm x
a)15^2-3x=0
b)(3x-2)(x+3)+(x^2-9)=0
c) (x-1)^2-(x+10(2-3×0=-3

Comments ( 2 )

  1. a) 15^2 – 3x = 0
                   3x = 15^2
                   3x = 225
                     x = 225 : 3
                     x = 75
    b) ( 3x – 2 )( x + 3 ) + ( x^2 – 9 ) = 0
         ( 3x – 2 )( x + 3 ) + ( x^2 – 3^2 ) = 0
         ( 3x – 2 )( x + 3 ) + ( x – 3 )( x + 3 ) = 0
        ( 3x – 2 + x – 3 )( x + 3 ) = 0
         ( 4x – 5 )( x + 3 ) = 0
    ⇔ 4x – 5 = 0
    => 4x      = 5
    =>   x      = 5/4
    ⇔ x + 3 = 0
    => x      = -3
     

  2. a) 15^2 – 3x = 0
                   3x = 15^2
                   3x = 225
                     x = 225 : 3
                     x = 75
    b) ( 3x – 2 )( x + 3 ) + ( x^2 – 9 ) = 0
         ( 3x – 2 )( x + 3 ) + ( x^2 – 3^2 ) = 0
         ( 3x – 2 )( x + 3 ) + ( x – 3 )( x + 3 ) = 0
        ( 3x – 2 + x – 3 )( x + 3 ) = 0
         ( 4x – 5 )( x + 3 ) = 0
    ⇔ 4x – 5 = 0
    => 4x      = 5
    =>   x      = 5/4
    ⇔ x + 3 = 0
    => x      = -3
    c) ( x – 1 )^2 – ( x + 1)( 2 – 3x ) = -3
        ( x – 1 )( x – 1 ) + ( x – 1 )( 3x – 2 ) = -3
        ( x – 1 )( x – 1 + 3x – 2 )  = -3
        ( x – 1 )( 4x – 3 ) = -3
    Ta có : -3 = 3.(-1) = (-1).3
    TH1 :
    ⇔ x – 1 = -1
    => x      = 0
    ⇔ 4x – 3 = 3
    => 4x      = 6
    =>   x      = 3/2
    TH2 :
    ⇔ x – 1 = 3
    => x      = 4
    ⇔ 4x – 3 = -1
    => 4x     = 2
    =>   x     = 1/2
     

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222-9+11+12:2*14+14 = ? ( )

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