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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Tìm x (x-5).(x+2)+(x+1).(2-x)=15

Toán Lớp 8: Tìm x
(x-5).(x+2)+(x+1).(2-x)=15

Comments ( 2 )

  1. $MID$
    $(x-5)(x+2)+(x+1)(2-x)=15$
    $[(x-5)(x+2)]+[(x+1)(2-x)]=15$
    $(x^{2}+2x-5x-10)+(2x-x^{2}+2-x)=15$
    $x^{2}+2x-5x-10+2x-x^{2}+2-x=15$
    $-2x-8=15$
    $-2x=15+8$
    $-2x=23$
    $=>x=\frac{-23}{2}$
    $\frac{chúc-bạn-học-tốt}{mình-xin-hay-nhất-nha}$

  2. Lời giải:
    (x-5)(x+2)+(x+1)(2-x)=15
    ⇔x^(2)+2x-5x-10+2x-x^(2)+2-x=15
    ⇔(x^(2)-x^2)+(2x-5x+2x-x)+(-10+2)=15
    ⇔-2x-8=15
    ⇔-2x=23
    ⇔x=-23/2
    Vậy x=-23/2
     

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222-9+11+12:2*14+14 = ? ( )