Toán Lớp 8: Thực hiện phép tính: $\frac{3x+10}{x+3}$-$\frac{x+4}{x+3}$
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Toán Lớp 8: Thực hiện phép tính: $\frac{3x+10}{x+3}$-$\frac{x+4}{x+3}$
Comments ( 2 )
$\dfrac{3x+10}{x+3}-\dfrac{x+4}{x+3}$
$=\dfrac{3x+10-\left(x+4\right)}{x+3}$
$=\dfrac{2x+6}{x+3}$
$=\dfrac{2\left(x+3\right)}{x+3}$
$=2$
Bạn tham khảo, có sai sót mong giúp đỡ