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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Rút gọn a)2x(1-x)+(x+3)(2x-3) b)(x+2)^2-(x+1)(x-1) c) x/x+2+2x/x-2-3x^2+4/x^2-4 giúp mik vs ạ

Toán Lớp 8: Rút gọn
a)2x(1-x)+(x+3)(2x-3)
b)(x+2)^2-(x+1)(x-1)
c) x/x+2+2x/x-2-3x^2+4/x^2-4
giúp mik vs ạ

Comments ( 2 )

  1. Giải đáp:
    a) $=5x-9$
    b) $=4x+5$
    c) $=\frac{-3x^4+9x^3-16x^2-8}{\left(x+2\right)\left(x-2\right)\left(-3x^2+x-2\right)}$
    Lời giải và giải thích chi tiết:
    a) $2x\left(1-x\right)+\left(x+3\right)\left(2x-3\right)$
    $=2x-2x^2+\left(x+3\right)\left(2x-3\right)$
    $=2x-2x^2+2x^2+3x-9$
    $=2x+3x-9$
    $=5x-9$
    b) $\left(x+2\right)^2-\left(x+1\right)\left(x-1\right)$
    $=x^2+4x+4-\left(x+1\right)\left(x-1\right)$
    $=x^2+4x+4-x^2+1$
    $=x^2-x^2+4x+4+1$
    $=4x+4+1$
    $=4x+5$
    c) $\frac{x}{x+2}+\frac{2x}{x-2-3x^2}+\frac{4}{x^2-4}$
    $=\frac{x\left(x-2\right)\left(-3x^2+x-2\right)}{\left(x+2\right)\left(x-2\right)\left(-3x^2+x-2\right)}+\frac{2x\left(x+2\right)\left(x-2\right)}{\left(x+2\right)\left(x-2\right)\left(-3x^2+x-2\right)}+\frac{4\left(-3x^2+x-2\right)}{\left(x+2\right)\left(x-2\right)\left(-3x^2+x-2\right)}$
    $=\frac{x\left(x-2\right)\left(-3x^2+x-2\right)+2x\left(x+2\right)\left(x-2\right)+4\left(-3x^2+x-2\right)}{\left(x+2\right)\left(x-2\right)\left(-3x^2+x-2\right)}$
    $=\frac{-3x^4+9x^3-16x^2-8}{\left(x+2\right)\left(x-2\right)\left(-3x^2+x-2\right)}$

  2. Giải đáp+Lời giải và giải thích chi tiết:
    a)
    2x(1 – x) + (x + 3)(2x – 3)
    = 2x – 2x^2 + (2x^2 – 3x + 6x – 9)
    = 2x – 2x^2 + (2x^2 + 3x – 9)
    = 2x – 2x^2 + 2x^2 + 3x – 9
    = (2x^2 – 2^2) + (3x + 2x) – 9
    = 5x – 9
    b)
    (x + 2)^2 – (x + 1)(x – 1)
    = (x^2 + 2.x.2 + 2^2)  – (x^2 – 1)
    = (x^2 + 4x + 4) – x^2 + 1
    = x^2 + 4x + 4 – x^2 + 1
    = (x^2 – x^2) + 4x + (4 + 1)
    = 4x + 5
    c)
    x/{x + 2} + {2x}/{x – 2} – {3x^2 + 4}/{x^2 – 4}         (ĐKXĐ: x ne +- 2)
    = x/{x + 2} + {2x}/{x – 2} – {3x^2 + 4}/{x^2 – 2^2} 
    = x/{x + 2} + {2x}/{x – 2} – {3x^2 + 4}/{(x – 2)(x + 2)} 
    = {x(x – 2)}/{(x – 2)(x + 2)} + {2x(x + 2)}/{(x – 2)(x + 2)} – {3x^2 + 4}/{(x – 2)(x + 2)} 
    = {x^2 – 2x}/{(x – 2)(x + 2)} + {2x^2 + 4x}/{(x – 2)(x + 2)} – {3x^2 + 4}/{(x – 2)(x + 2)} 
    = {x^2 – 2x + 2x^2 + 4x – (3x^2 + 4)}/{(x – 2)(x + 2)} 
    = {x^2 – 2x + 2x^2 + 4x – 3x^2 – 4}/{(x – 2)(x + 2)} 
    = {(x^2 + 2x^2 – 3x^2) + (4x – 2x) – 4}/{(x – 2)(x + 2)} 
    = {2x – 4}/{(x – 2)(x + 2)} 
    = {2(x – 2)}/{(x – 2)(x + 2)} 
    = 2/{x + 2}
    #SunHee

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222-9+11+12:2*14+14 = ? ( )