Toán Lớp 8: Quy đồng mẫu thức hai phân thức sau :x+4\x^2-2x+1,x+3\x-x^2
Leave a reply
Register Now
Login
Lost Password
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Toán Lớp 8: Quy đồng mẫu thức hai phân thức sau :x+4\x^2-2x+1,x+3\x-x^2
Comments ( 1 )
\dfrac{{x + 4}}{{{x^2} – 2x + 1}};\dfrac{{x + 3}}{{x – {x^2}}}\\
+ {x^2} – 2x + 1 = {\left( {x – 1} \right)^2} = {\left( {1 – x} \right)^2}\\
+ x – {x^2} = x\left( {1 – x} \right)\\
\Leftrightarrow MTC = x.{\left( {1 – x} \right)^2}\\
+ )\dfrac{{x + 4}}{{{x^2} – 2x + 1}} = \dfrac{{\left( {x + 4} \right).x}}{{x{{\left( {1 – x} \right)}^2}}} = \dfrac{{{x^2} + 4x}}{{x.{{\left( {1 – x} \right)}^2}}}\\
+ )\dfrac{{x + 3}}{{x – {x^2}}} = \dfrac{{\left( {x + 3} \right).\left( {1 – x} \right)}}{{x.{{\left( {1 – x} \right)}^2}}} = \dfrac{{ – {x^2} – 2x + 3}}{{x.{{\left( {1 – x} \right)}^2}}}
\end{array}$