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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: PTĐTTNT: $\text{3}$$x^{2}$ – $\text{6}$$\textit{xy}$ + $\text{3}$$y^{2}$ – $\text{12}$

Home/ Toán Lớp 8: PTĐTTNT: $\text{3}$$x^{2}$ – $\text{6}$$\textit{xy}$ + $\text{3}$$y^{2}$ – $\text{12}$

Toán Lớp 8: PTĐTTNT: $\text{3}$$x^{2}$ – $\text{6}$$\textit{xy}$ + $\text{3}$$y^{2}$ – $\text{12}$

Tháng Mười 28, 2022 Toán học 2 Comments 0 views

Toán Lớp 8: PTĐTTNT: $\text{3}$$x^{2}$ – $\text{6}$$\textit{xy}$ + $\text{3}$$y^{2}$ – $\text{12}$

Comments ( 2 )

  1. thanhmaianh
    thanhmaianh
    28 Tháng Mười, 2022 at 9:06 sáng
    Reply
        3x² – 6xy + 3y² – 12
    = 3 ( x² – 2xy + y² – 4 )
    = 3 [ ( x² – 2xy + y² ) – 4 ]
    = 3 [ ( x – y )² – 4 ]
    = 3 [ ( x – y )² – 2² ]
    = 3 [ ( x – y – 2 ) ( x – y + 2 ) ]
    = 3 ( x – y – 2 ) ( x – y + 2 )
     Áp dụng HĐT thứ 3 : a² – b² = ( a – b ) ( a + b )
     

  2. maianh67
    maianh67
    28 Tháng Mười, 2022 at 9:05 sáng
    Reply
    3x^2-6xy+3y^2-12
    =3.x^2-3.2xy+3.y^2-3.4
    =3.(x^2-2xy+y^2-4)
    =3.[(x^2-2xy+y^2)-2^2]
    =3.[(x-y)^2-2^2]
    =3.(x-y-2)(x-y+2)

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222-9+11+12:2*14+14 = ? ( )

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