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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: PTĐTTNT: x^4 – 6x^3 + 12x^2 – 14x + 3

Toán Lớp 8: PTĐTTNT: x^4 – 6x^3 + 12x^2 – 14x + 3

Comments ( 2 )

  1.  $= x^4 – 6x^3 + 12x^2 – 14x + 3$
     $= (x^4 – 2x^3 + 3x^2) + (- 4x^3 + 8x^2 – 12x) + (x^2 – 2x + 3 )$
    $= x^2.( x^2 – 2x + 3 ) – 4x.(x^2 – 2x + 3 ) + (x^2 – 2x + 3)$
     $=( x^2 – 2x + 3 ).( x^2 – 4x + 1 )$
    $⇒ ( x^2 – 2x + 3 ).( x^2 – 4x + 1 )$
     $#Xin hay nhất$

  2. Giải đáp + Lời giải và giải thích chi tiết:
             x^4 – 6x^3 + 12x^2 – 14x + 3
     = x^4 – 6x^3 + 12x^2 – 14x + 3
     = (x^4 – 2x^3 + 3x^2) + (- 4x^3 + 8x^2 – 12x) + (x^2 – 2x + 3 )
     = x^2.( x^2 – 2x + 3 ) – 4x.(x^2 – 2x + 3 ) + (x^2 – 2x + 3)
     =( x^2 – 2x + 3 ).( x^2 – 4x + 1 )
     -> ( x^2 – 2x + 3 ).( x^2 – 4x + 1 )
    #nhulinh0

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222-9+11+12:2*14+14 = ? ( )

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