Toán Lớp 8: Phân tích thành nhan tử
(a² + b²-5) ²-2 (ab+ 2)²
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Toán Lớp 8: Phân tích thành nhan tử
(a² + b²-5) ²-2 (ab+ 2)²
Comments ( 2 )
$=(a^2+b^2-5-2ab-4)(a^2+b^2-5+2ab+4)$
$=[(a-b)^2-9][(a+b)^2-1]$
$=(a-b-3)(a-b+3)(a+b-1)(a+b+1)$