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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Phân tích đa thức thành nhân tử: a( b ³ -c ³ ) +b(c³- a³)+ c(a³ – b³)

Toán Lớp 8: Phân tích đa thức thành nhân tử:
a( b ³ -c ³ ) +b(c³- a³)+ c(a³ – b³)

Comments ( 2 )

  1. $\\$
    a(b^3-c^3)+b(c^3-a^3)+c(a^3-b^3)
    =a(b^3-c^3) + bc^3-a^3b +a^3c – b^3c
    = a(b^3-c^3) + bc (c^2 – b^2) – a^3 (b-c)
    = a(b-c)(b^2+bc+c^2)- bc (b-c)(b+c) – a^3(b-c)
    = (b-c)(ab^2+abc +ac^2 – b^2c -bc^2 -a^3)
     =  (c-b)(a^3 – ab^2 – abc -ac^2 + b^2c+bc^2)
    = (c-b) [(b^2c-ab^2) + (bc^2-abc) + (a^3 – ac^2)]
    =(c-b) [b^2 (c-a) + bc (c-a) – a (c-a)(c+a)]
    =(c-b) [(c-a) (b^2+bc – ac – a^2)]
    = (c-b)(c-a)[(b-a)(b+a)+ c(b-a)]
    = (c-b)(c-a)(a+b+c)(b-a)

  2. Giải đáp + Lời giải và giải thích chi tiết:
    a(b^3-c^3)+b(c^3-a^3)+c(a^3-b^3)
    = a(b^3-c^3)+bc^3-ba^3+ca^3-cb^3
    = a(b^3-c^3)-cb^3+bc^3-ba^3+ca^3
    = a(b^3-c^3)-bc(b^2-c^2)-a^3(b-c)
    = a(b-c)(b^2+bc+c^2)-bc(b-c)(b+c)-a^3(b-c)
    = (b-c)[a(b^2+bc+c^2)-bc(b+c)-a^3]
    = (b-c)(ab^2+abc+ac^2-b^2c-bc^2-a^3)
    = (b-c)[(ab^2-b^2c)+(abc-bc^2)-(a^3-ac^2)]
    = (b-c)[b^2(a-c)+bc(a-c)-a(a-c)(a+c)]
    = (b-c)(a-c)(b^2+bc-a^2-ac)
    = (b-c)(a-c)[(b^2-a^2)+(bc-ac)]
    = (b-c)(a-c)[(b-a)(b+a)+c(b-a)]
    = (b-c)(a-c)(b-a)(b+a+c)

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222-9+11+12:2*14+14 = ? ( )

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