Toán Lớp 8: Phân Tích Đa Thức Thành Nhân Tử
1) 4a^2-4a^2b^3+b^6
2) 9-x^2
3) 4x^2-1
4) 16y^2-x^4
5) x^3+3x^2+3x+1
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Toán Lớp 8: Phân Tích Đa Thức Thành Nhân Tử
1) 4a^2-4a^2b^3+b^6
2) 9-x^2
3) 4x^2-1
4) 16y^2-x^4
5) x^3+3x^2+3x+1
Comments ( 1 )
1)4{a^2} – 4a{b^3} + {b^6}\\
= {\left( {2a} \right)^2} – 2.2a.{b^3} + {\left( {{b^3}} \right)^2}\\
= {\left( {2a – {b^3}} \right)^2}\\
2)9 – {x^2} = \left( {3 – x} \right)\left( {3 + x} \right)\\
3)4{x^2} – 1 = \left( {2x – 1} \right)\left( {2x + 1} \right)\\
4)16{y^2} – {x^4} = \left( {4y – {x^2}} \right)\left( {4y + {x^2}} \right)\\
5){x^3} + 3{x^2} + 3x + 1\\
= {\left( {x + 1} \right)^3}
\end{array}$