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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Kết quả phép tính 24x^5y^3z : 6x^3y^2z là: thực hiện a) 2x(x^2 – 3x +1) b) (12x^3y – 9x^2y^2+ 21x^4y^3) : (3x

Toán Lớp 8: Kết quả phép tính 24x^5y^3z : 6x^3y^2z là:
thực hiện
a) 2x(x^2 – 3x +1)
b) (12x^3y – 9x^2y^2+ 21x^4y^3) : (3xy)

Comments ( 2 )

  1. 24x^5 y³ z : 6x³y²z
    =4x²y
    a) 2x(x² – 3x +1)
    = 2x.x² – 2x.3x + 2x.1
    =2x³ – 6x² + 2x
    b) (12x³y – 9x²y² + 21x^4y³) : 3xy
    = 12x³y : 3xy – 9x²y² : 3xy + 21x^4y³ : 3xy
    =4x² – 3xy + 7x²y²

  2. #andy
    \[\begin{array}{l}
    a)24{x^5}{y^3}z:6{x^3}{y^2}z\\
     = \left( {24:6} \right)\left( {{x^5}:{x^3}} \right)\left( {{y^3}:{y^2}} \right)\left( {z:z} \right)\\
     = 4{x^2}y\\
    b)2x\left( {x – 3x + 1} \right)\\
     = \left( {2x.{x^2}} \right) – \left( {2x.3x} \right) + \left( {2x.1} \right)\\
     = 2x – 6x + 2x\\
    c)\left( {12xy – 9xy + 21{x^4}y} \right):3xy\\
     = \left( {12{x^3}y:3xy} \right) – \left( {9{x^2}{y^2}:3xy} \right) + \left( {21{x^4}{y^3}:3xy} \right)\\
     = 4{x^2} – 3xy + 7{x^2}{y^2}
    \end{array}\]

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222-9+11+12:2*14+14 = ? ( )

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