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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: GIÚP MK VS HỨA TRẢ ĐỦ 1,(2X-5) ²-(3-X) ²=0 2.5X ³-45x=0 3,5(x-3)=x ² -6x+9 4,(x ²-9)(x ²+x+1)=0

Toán Lớp 8: GIÚP MK VS HỨA TRẢ ĐỦ
1,(2X-5) ²-(3-X) ²=0
2.5X ³-45x=0
3,5(x-3)=x ² -6x+9
4,(x ²-9)(x ²+x+1)=0

Comments ( 1 )

  1. Giải đáp + Lời giải và giải thích chi tiết !
    to Tìm x:
    1)
    (2x-5)^2-(3-x)^2 = 0
    <=> (2x-5-3+x)(2x-5+3-x) = 0
    <=> (3x-8)(x-2) = 0
    <=> \(\left[ \begin{array}{l}3x-8=0\\x-2=0\end{array} \right.\) 
    <=> \(\left[ \begin{array}{l}3x=8\\x=2\end{array} \right.\) 
    <=> \(\left[ \begin{array}{l}x=\dfrac{8}{3}\\x=2\end{array} \right.\) 
    Vậy S= {8/3; 2}
    Áp dụng: a^2-b^2 = (a-b)(a+b)
    2)
    5x^3-45x = 0
    <=> 5x(x^2-9) = 0
    <=> \(\left[ \begin{array}{l}5x=0\\x^2-9=0\end{array} \right.\) 
    <=> \(\left[ \begin{array}{l}x=0\\x^2=9\end{array} \right.\) 
    <=> \(\left[ \begin{array}{l}x=0\\x=3\\x=-3\end{array} \right.\) 
    Vậy S= {0; 3; -3}
    3)
    5(x-3) = x^2-6x+9
    <=> 5(x-3) = (x-3)^2
    <=> 5(x-3)-(x-3)^2 = 0
    <=> (x-3)(5-x+3) = 0
    <=> (x-3)(8-x) = 0
    <=> \(\left[ \begin{array}{l}x-3=0\\8-x=0\end{array} \right.\) 
    <=> \(\left[ \begin{array}{l}x=3\\x=8\end{array} \right.\) 
    Vậy S= {3; 8}
    Áp dụng: 
    +) (a-b)^2 = a^2-2ab+b^2
    +) a^2-b^2 = (a-b)(a+b)
    4)
    (x^2-9)(x^2+x+1) = 0
    <=> (x^2-9)[(x^2+x+1/4)+3/4] = 0
    <=> (x^2-9)[(x+1/2)^2+3/4] = 0
    <=> \(\left[ \begin{array}{l}x^2-9=0\\(x+\dfrac{1}{2})^2+\dfrac{3}{4}=0\end{array} \right.\) 
    <=> \(\left[ \begin{array}{l}x^2=9\\(x+\dfrac{1}{2})^2= -\dfrac{3}{4}\end{array} \right.\) 
    Vì (x+1/2)^2 >= 0 AA x
    Mà (x+1/2)^2 = -(3)/4 (vô lý)
    <=> x^2 = 9
    <=> \(\left[ \begin{array}{l}x=3\\x=-3\end{array} \right.\) 
    Vậy S= {3; -3}
     

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222-9+11+12:2*14+14 = ? ( )