Toán Lớp 8: giải pt: $\dfrac{2-x}{2017}$ -1=$\dfrac{1-x}{2018}$ -$\dfrac{x}{2019}$
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Toán Lớp 8: giải pt: $\dfrac{2-x}{2017}$ -1=$\dfrac{1-x}{2018}$ -$\dfrac{x}{2019}$
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(2-x)/2017 – 1 =(1-x)/2018 -x/2019
<=>(2-x)/2017 +1 = (1-x)/2018+1 – x/2019+1
<=>(2-x+2017)/2017 = (1-x +2018)/2018 + (2019-x)/2019
<=> (2019-x)/2017 – (2019-x)/2018 – (2019-x)/2019=0
<=>(2019-x)(1/2017 – 1/2018 – 1/2019)=0
Do 1/2017 – 1/2018 – 1/2019\ne 0
<=>2019-x=0
<=>x=2019
Vậy S={2019}