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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Giải phương trình : x^2 – 6x + 9 = 0 x^2 – x + 6 = 0 x^2 – 2x – 8 = 0

Toán Lớp 8: Giải phương trình :
x^2 – 6x + 9 = 0
x^2 – x + 6 = 0
x^2 – 2x – 8 = 0

Comments ( 2 )

  1. x^{2} – 6x + 9 = 0
    (x-3)^{2}=0
    =>x=3
    ———————————-
    x^{2}-x + 6 = 0
    x^{2}-x+24/4=0
    x^{2}-x+1/4+23/4=0
    (x+1/2)^{2}+23/4=0
    (x-1/2)^{2}=-23/4
    Vì (x-1/2)^{2} sẽ ra số tự nhiên 
    => Phương trình vô nghiệm 
    —————————————
    x^{2} – 2x – 8 = 0
    x^{2}-4x+2x-8=0
    x(x-4)+2(x-4)=0
    (x-4)(x+2)=0
    =>\(\left[ \begin{array}{l}x-4=0\\x+2=0\end{array} \right.\) 
    =>\(\left[ \begin{array}{l}x=-2\\x=4\end{array} \right.\) 
     

  2. 1) x^2 – 6x + 9 = 0 $\\$ \Leftrightarrow ( x-3)^2 = 0 $\\$ \Leftrightarrow x =3 $\\$ Vậy : S = {3} $\\$ 2) x^2 – x + 6 = 0 $\\$ \Leftrightarrow x ^2 – x + 1/4 + 23/4 = 0 $\\$ \Leftrightarrow (x-1/2)^2 + 23/4 =0 $\\$ \Leftrightarrow (x-1/2)^2 = -23/4 (vô lí) $\\$ $\text{Vậy : Phương trình vô nghiệm}$ $\\$ 3) x^2 – 2x – 8 = 0 $\\$ \Leftrightarrow x^2 – 4x +2x – 8 = 0 $\\$ \Leftrightarrow x(x-4) + 2(x-4) = 0 $\\$ \Leftrightarrow (x+2)(x-4) = 0 $\\$ \Leftrightarrow \(\left[ \begin{array}{l}x+2 = 0\\x-4 = 0\end{array} \right.\) $ \Leftrightarrow$ \(\left[ \begin{array}{l}x=-2\\x=4\end{array} \right.\) $\\$ Vậy : S = {-2;4} $\\$ $\text{Chúc bạn học tốt.}$

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222-9+11+12:2*14+14 = ? ( )

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