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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: $\frac{x}{x+3}$- $\frac{7x}{x^2+3x}$

Toán Lớp 8: $\frac{x}{x+3}$- $\frac{7x}{x^2+3x}$

Comments ( 2 )

  1. Giải đáp:
    $\dfrac{x}{x+3}-\dfrac{7x}{x^2+3x}$ $=\dfrac{x}{x+3}-\dfrac{7x}{x.(x+3)}$ $= \dfrac{x.x}{(x+3).x}- \dfrac{7x}{x.(x+3)}$ $= \dfrac{x^2-7x}{x.(x+3)}$ $=\dfrac{x.(x-7)}{x.(x+3)}$  $=\dfrac{x-7}{x+3}$
     

  2. x/(x+3)-(7x)/(x^2+3x)
    =x/(x+3)-(7x)/(x(x+3))
    =(x-7)/(x+3)
    =(x-7)/(x+3)
    Xin hay nhất cho nhóm ạ

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222-9+11+12:2*14+14 = ? ( )