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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Dùng hằng đẳng thức,tính: (2x-3)^3 (a+2b)^3 (a+b+c)^2 (a-b-c)^2 Giúp em trong đêm ạ

Toán Lớp 8: Dùng hằng đẳng thức,tính:
(2x-3)^3
(a+2b)^3
(a+b+c)^2
(a-b-c)^2
Giúp em trong đêm ạ

Comments ( 2 )

  1.  (2x-3)³
    = (2x)³-3.(2x)².3+3.2x.3²-3³
    = 8x³-36x²+54x-27
    (a+2b)³
    = a³+3.a².2b+3.a.(2b)²+(2b)³
    = a³+6a²b+12ab²+8b³
    (a+b+c)²
    C1:
    =(a+b+c).(a+b+c)
    = a²+ab+ac+ab+b²+bc+ac+bc+c²
    = a²+(ab+ab)+(ac+ac)+b²+(bc+bc)+c²
    = a²+2ab+2ac+b²+2bc+c²
    C2:
    = [(a+b)+c]²
    = (a+b)²+ 2.(a+b).c+c²
    = a²+2ab+b²+(2a+2b).c+c²
    = a²+2ab+b²+2ac+2bc+c²
    (a-b-c)²
    C1
    = (a-b-c).(a-b-c)
    = a²-ab-ac-ab+b²+bc-ac+bc+c²
    = a²-(ab+ab)-(ac+ac)+b²+(bc+bc)+c²
    = a²-2ab-2ac+b²+2bc+c²
    #anhnguyenff

  2. (2x-3)^3 = (2x)^2 – 3. (2x)^2 .3 + 3. 2x .3^2 – 3^3
                    = 8x^3 – 36x^2  + 54x – 27
    (a+2b)^3 = a^3 + 3.a^2 .2b + 3.a. (2b)^2 + (2b)^3
                     =a^3 + 6a^2 b + 12ab^2 + 8a^3
    -> \text{Dùng HĐT số 5:} (A-B)^3 = A^3 – 3A^2 B + 3AB^2 – B^3
    (a+b+c)^2 = [(a+b) +c]^2
                       = (a+b)^2 + 2.(a+b).c + c^2
                      = a^2 + 2ab + b^2 +2ac + 2bc + c^2
    -> \text{Dùng HĐT số 1:}  (A+B)^2 = A^2 + 2AB +B^2
    (a-b-c)^2 = [(a-b) – c]^2
                     = (a-b)^2 – 2(a+b)c + c^2
                     = a^2 – 2ab + b^2 – 2ac – 2bc + c^2
    -> \text{Dùng HĐT số 2:}   (A-B)^2 = A^2 – 2AB +B^2

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222-9+11+12:2*14+14 = ? ( )