Register Now

Login

Lost Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: CMR: (x+y+z)^3 = x^3 + y^3 + z^3 + 3(x+y)(y+z)(z+x)

Toán Lớp 8: CMR: (x+y+z)^3 = x^3 + y^3 + z^3 + 3(x+y)(y+z)(z+x)

Comments ( 2 )

  1. (x+y+z)^3 = x^3 + y^3 + z^3 + 3(x+y)(y+z)(z+x)
    (x+y+z)^3 = x^3 + y^3 +z^3 +3xyz +3xz^2 +3yx^2 +3zx^2 +3xy^2 +3xyz+3zy^2+3yz^2
    (x+y+z)^3 = x^3 + 3x^2 y+3y^2 x+y^3 +3x^2 z+6xyz+3y^2 z+3xz^2 +z^3
    (x+y+z)^3 = (x+y)^3 +3z(x+y)^2 +3z^2 (x+y) +z^3
    (x+y+z)^3 = (x+y+z)^3
    => (x+y+z)^3 = x^3 + y^3 + z^3 + 3(x+y)(y+z)(z+x)
     

  2. ~rai~
    \((x+y+z)^3=x^3+y^3+z^3+3(x+y)(y+z)(z+x)\\\text{Xét VT=}(x+y+z)^3\\\quad\quad\quad=[(x+y)+z]^3\\\quad\quad\quad=(x+y)^3+3(x+y)^2.z+3(x+y).z^2+z^3\\\quad\quad\quad=x^3+3x^2y+3xy^2+y^3+3z(x^2+2xy+y^2)+3xz+3yz+z^3\\\quad\quad\quad=x^3+y^3+z^3+3x^2y+3xy^2+3x^2z+6xyz+3y^2z+3xz^2+3yz^2\\\\\quad\quad\quad=x^3+y^3+z^3+(3xy^2+3xy^2)+(3x^2z+3xyz)+(3xyz+3y^2z)+(3xz^2+3yz^2)\\\quad\quad\quad=x^3+y^3+z^3+3xy(x+y)+3xz(x+y)+3yz(x+y)+3z^2(x+y)\\\quad\quad\quad=x^3+y^3+z^3+3(x+y)(xy+xz+yz+z^2)\\\quad\quad\quad=x^3+y^3+z^3+3(x+y)[(xy+xz)+(yz+z^2)]\\\quad\quad\quad=x^3+y^3+z^3+3(x+y)[x(y+z)+z(y+z)]\\\quad\quad\quad=x^3+y^3+z^3+3(x+y)(y+z)(z+x)\\\quad\quad\quad=VP.\\\Rightarrow (x+y+z)^3=x^3+y^3+z^3+3(x+y)(y+z)(z+x).\quad(đpcm)\)

Leave a reply

222-9+11+12:2*14+14 = ? ( )

About Kim Dung