Toán Lớp 8: a)$\frac{3}{x(x+2)}$+$\frac{x-1}{x^2-2x}$
Leave a reply
Register Now
Login
Lost Password
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Toán Lớp 8: a)$\frac{3}{x(x+2)}$+$\frac{x-1}{x^2-2x}$
Comments ( 2 )
Giải đáp+Lời giải và giải thích chi tiết:
(3)/[x(x+2)]+(x-1)/(x^2-2x)
=(3)/[x(x+2)]+(x-1)/[x(x-2)]
=[3(x-2)]/[x(x+2)(x-2)]+[(x-1)(x+2)]/[x(x+2)(x-2)]
=(3x-6)/[x(x+2)(x-2)]+(x^2+x-2)/[x(x+2)(x-2)]
=(3x-6+x^2+x-2)/[x(x+2)(x-2)]
=(x^2+4x-8)/[x(x+2)(x-2)]
#LinhSad
3/(x(x+2))+(x-1)/(x^2-2x)
=3/(x(x+2))+(x-1)/(x(x-2))
=(3(x-2)+(x-1)(x+2))/(x(x-2)(x+2))
=(3x-6+x^2+2x-x-2)/(x(x-2)(x+2))
=(x^2+4x-8)/(x(x-2)(x+2))