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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: A = a( b2 – c2 ) + b( c2 – a2 ) + c( a2 – b2 )

Toán Lớp 8: A = a( b2 – c2 ) + b( c2 – a2 ) + c( a2 – b2 )

Comments ( 1 )

  1. Giải đáp:
     A =a(b^2 – c^2) + b(c^2 – a^2) + c(a^2 – b^2)
    = a[-(a^2 – b^2) – (c^2 – a^2)] + b(c^2 – a^2) + c(a^2 – b^2)
    = [b(c^2 – a^2) – a(c^2 – a^2)] + [c(a^2 – b^2) – a(a^2 – b^2)]
    =(c^2 – a^2)(b – a) + (a^2 – b^2)(c – a)
    = (c^2 – a^2)(b – a) – (b^2 – a^2)(c – a)
    = (c- a)(c + a)(b – a) – (b – a)(b + a)(c – a)
    = (c – a)(b – a)(c + a – b – a)
    = (c – a)(b – a)(c – b)
    C2:  A =a(b^2 – c^2) + b(c^2 – a^2) + c(a^2 – b^2)
    = ab^2 – ac^2 + bc^2 – a^2 b + a^2 c – cb^2
    = (ab^2 – cb^2) + (a^2 c – ac^2) – (a^2 b – bc^2)
    = b^2 (a – c) + ac(a – c) – b(a^2 – c^2)
    = b^2 (a – c) + ac(a – c) – b(a – c)(a + c)
    = (a – c)[b^2 + ac – b(a + c)]
    = (a – c)(b^2 + ac – ab – bc)
    = (a – c)[(b^2 – ab) – (bc – ac)]
    = (a – c)[b(b -a ) – c(b – a)]
    = (a – c)(b – a)(b – c)

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222-9+11+12:2*14+14 = ? ( )