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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: A)(a+b)²-(a-b)² B)(a+b)³-(a-b)³-2b³ C)(x+y+z)²-2(x+y+z)(x+y)+(x+y)² Bài 2 A) 34²+66²+68×66 B)74²+24²-48×74

Toán Lớp 8: A)(a+b)²-(a-b)²
B)(a+b)³-(a-b)³-2b³
C)(x+y+z)²-2(x+y+z)(x+y)+(x+y)²
Bài 2
A) 34²+66²+68×66
B)74²+24²-48×74

Comments ( 2 )

  1. Giải đáp:
     Bài 1:
    a)=4ab
    b)=6a^2 b
    c)=z^2
    Bài 2:
    a)=10000
    b)=2500
    Lời giải và giải thích chi tiết:
     Bài 1:
    a) (a+b)^2 -(a-b)^2
    =(a+b-a+b)(a+b+a-b)
    =2b.2a
    =4ab
    b) (a+b)^3 -(a-b)^3 -2b^3
    =a^3 +3a^2 b+3ab^2 +b^3 -a^3 +3a^2 b-3ab^2 +b^3 -2b^3
    =3a^2 b +3a^2 b
    =6a^2 b
    c) (x+y+z)^2 -2(x+y+z)(x+y) + (x+y)^2
    =(x+y+z-x-y)^2
    =z^2
    Bài 2 :
    a) 34^2 +66^2 +68.66
    =34^2 +68.66+66^2
    =34^2 +2.34.66+66^2
    =(34+66)^2
    =100^2
    =10000
    b) 74^2 +24^2 -48.74
    =24^2 -48.74+74^2
    =24^2 -2.24.72+74^2
    =(24-74)^2
    =(-50)^2
    =2500

  2. Bài 1:
    a/ (a+b)^2-(a-b)^2
    = (a+b-a+b)(a+b+a-b)
    = 2a.2b = 4ab
    b/ (a+b)^3-(a-b)^3-2b^3
    = a^3+3a^2b+3ab^2+b^3-a^3+3a^2b-3ab^2+b^2-2b^3
    = 6a^2b
    c/ (x+y+z)^2-2(x+y+z)(x+y)+(x+y)^2
    = (x+y+z-x-y)^2
    = z^2
    Bài 2:
    a/ 34^2+66^2+68.66
    = (34+66)^2
    = 100^2 = 10000
    b/ 74^2+24^2-48.74
    = (74-24)^2 = 50^2
    = 2500

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222-9+11+12:2*14+14 = ? ( )