Toán Lớp 8: A) (-4x mũ 3+2/3x mũ 2-1).2x
B)(2x mũ 3-x mũ 2+x+1):(2x+1)
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Toán Lớp 8: A) (-4x mũ 3+2/3x mũ 2-1).2x
B)(2x mũ 3-x mũ 2+x+1):(2x+1)
Comments ( 2 )
a) – 8{x^4} + \dfrac{4}{3}{x^3} – 2x\\
b){x^2} – x + 1
\end{array}\)
a)\left( { – 4{x^3} + \dfrac{2}{3}{x^2} – 1} \right).2x\\
= – 8{x^4} + \dfrac{4}{3}{x^3} – 2x\\
b)\dfrac{{2{x^3} – {x^2} + x + 1}}{{2x + 1}}\\
= \dfrac{{2{x^3} + {x^2} – 2{x^2} – x + 2x + 1}}{{2x + 1}}\\
= \dfrac{{{x^2}\left( {2x + 1} \right) – x\left( {2x + 1} \right) + \left( {2x + 1} \right)}}{{2x + 1}}\\
= \dfrac{{\left( {2x + 1} \right)\left( {{x^2} – x + 1} \right)}}{{2x + 1}}\\
= {x^2} – x + 1
\end{array}\)