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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: A=-x²-4x-2 B=-2x²-3x+5 C=(2-x)(x+4) D=-8x²+4xy-y²+3 Tìm Giá Trị Lớn Nhất ạ

Toán Lớp 8: A=-x²-4x-2
B=-2x²-3x+5
C=(2-x)(x+4)
D=-8x²+4xy-y²+3
Tìm Giá Trị Lớn Nhất ạ

Comments ( 1 )

  1. A = -x^2 – 4x – 2
    = -(x^2 + 4x + 2)
    =- (x^2 + 4x + 4 – 2)
    =-(x^2 + 4x + 4) +2
    = -(x-2)^2 + 2
    Vì -(x-2)^2 ≤ 0 ∀x
    ⇔ (x-2)^2 + 2 ≤ 2
    Hay A≤2
    text{Dấu ”=” xãy ra khi} x-2=0⇔x=2
    text{Vậy, maxA = 2} ⇔ x=2
    B=-2x^2-3x+5
     =-2(x^2+3x/2)+5
    =-2(x^2+2x 3/4 +9/16 – 9/16)+5
    =-2(x^2+2x 3/4 +9/16)+ 49/8
    =-2(x+3/4)^2 + 49/8
    Vì -2(x+3/4)^2 ≤ 0 ∀x
    ⇔ -2(x+3/4)^2 + 49/8 ≤ 49/8
    Hay B≤49/8
    text{Dấu ”=” xảy ra khi} x+3/4=0⇔x=-3/4
    text{Vậy, maxB} = 49/8 ⇔ x=-3/4
    C=(2-x)(x+4)
    =2x + 8-x^2-4x
    =-(x-1)^2 + 9 ≤ 9
    text{Dấu ”=” xảy ra khi} x-1=0⇔x=1
    text{Vậy maxC} =9⇔x=1
    D = -8x^2 + 4xy – y^2 + 3
        = -(4x^2 – 4xy + y^2) – 4x^2 + 3
        = -(2x-y)^2 – 4x^2 + 3 ≤ 3
    text{Dấu “=” xảy ra} ⇔ \(\left[ \begin{array}{l}2x-y=0\\4x^2=0\end{array} \right.\)
    ⇔ \(\left[ \begin{array}{l}2x=y\\x=0\end{array} \right.\)                               
     ⇔ x=y=0
    text{Vậy maxD} = 3⇔ x=y=0

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222-9+11+12:2*14+14 = ? ( )

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