Register Now

Login

Lost Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: a)(x-2)^2-(x-2)(3x+2)=0 b)(x-5)^2=9 c)2x^2+7x+6=0

Toán Lớp 8: a)(x-2)^2-(x-2)(3x+2)=0
b)(x-5)^2=9
c)2x^2+7x+6=0

Comments ( 2 )

  1. Giải đáp + Lời giải và giải thích chi tiết !
    to Tìm x:
    a)
    (x-2)^2-(x-2)(3x+2) = 0
    <=> (x-2)(x-2-3x-2) = 0
    <=> (x-2)(-2x-4) = 0
    <=> -2(x-2)(x+2) = 0
    <=> (x-2)(x+2) = 0
    <=> x^2-4 = 0
    <=> x^2 = 4
    <=> \(\left[ \begin{array}{l}x=2\\x=-2\end{array} \right.\) 
    Vậy S= {2; -2}
    b)
    (x-5)^2=9
    <=> (x-5)^2 = (+-3)^2
    <=> \(\left[ \begin{array}{l}x-5=3\\x-5=-3\end{array} \right.\) 
    <=> \(\left[ \begin{array}{l}x=8\\x=2\end{array} \right.\) 
    Vậy S= {8; 2}
    c)
    2x^2+7x+6 = 0
    <=> 2x^2+4x+3x+6 = 0
    <=> (2x^2+4x)+(3x+6) = 0
    <=> 2x(x+2)+3(x+2) = 0
    <=> (2x+3)(x+2) = 0
    <=> \(\left[ \begin{array}{l}2x+3=0\\x+2=0\end{array} \right.\) 
    <=> \(\left[ \begin{array}{l}2x=-3\\x=-2\end{array} \right.\) 
    <=> \(\left[ \begin{array}{l}x=-\dfrac{3}{2}\\x=-2\end{array} \right.\) 
    Vậy S= {-(3)/2; -2}
     

  2. Giải đáp:
     
    Lời giải và giải thích chi tiết:
    a) (x-2)^2-(x-2)(3x+2)=0
    ⇔ (x-2)[x-2-(3x+2)]=0
    ⇔ (x-2)(x-2-3x-2)=0
    ⇔ (x-2)(-2x-4)=0
    ⇔ \(\left[ \begin{array}{l}x-2=0\\-2x-4=0\end{array} \right.\) 
    ⇔ \(\left[ \begin{array}{l}x=2\\x=-2\end{array} \right.\) 
    Vậy S={-2;2}
    b) (x-5)^2=9
    ⇔ (x-5)^2-9=0
    ⇔ (x-5-3)(x-5+3)=0
    ⇔ (x-8)(x-2)=0
    ⇔ \(\left[ \begin{array}{l}x-2=0\\x-8=0\end{array} \right.\) 
    ⇔ \(\left[ \begin{array}{l}x=2\\x=8\end{array} \right.\) 
    Vậy S={8;2}
    c) 2x^2+7x+6=0
    ⇔ 2x^2+4x+3x+6=0
    ⇔ 2x(x+2)+3(x+2)=0
    ⇔ (2x+3)(x+2)=0
    ⇔ \(\left[ \begin{array}{l}x=-\dfrac{3}{2}\\x=-2\end{array} \right.\) 
    Vậy S={-3/2;-2}

Leave a reply

222-9+11+12:2*14+14 = ? ( )