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Toán Lớp 8: 49a^2-(3a-b)^2 (a+1)^2-(a-1)^2 (x+5)^2-x^2 (x+2)^2-9x^2 (7x-4)^2-(2x+1)^2 (3x+1)^2-(5x-1)^2

Home/ Toán Lớp 8: 49a^2-(3a-b)^2 (a+1)^2-(a-1)^2 (x+5)^2-x^2 (x+2)^2-9x^2 (7x-4)^2-(2x+1)^2 (3x+1)^2-(5x-1)^2

Toán Lớp 8: 49a^2-(3a-b)^2 (a+1)^2-(a-1)^2 (x+5)^2-x^2 (x+2)^2-9x^2 (7x-4)^2-(2x+1)^2 (3x+1)^2-(5x-1)^2

Linh Tháng Bảy 17, 2022 Toán học 1 Comment 0 views

Toán Lớp 8: 49a^2-(3a-b)^2
(a+1)^2-(a-1)^2
(x+5)^2-x^2
(x+2)^2-9x^2
(7x-4)^2-(2x+1)^2
(3x+1)^2-(5x-1)^2

Comments ( 1 )

bichhhathu
17 Tháng Bảy, 2022 at 8:50 chiều

Reply

Giải đáp + Lời giải và giải thích chi tiết:

$#hyn$

$49a^2-(2a-b)^2$

$=(7a)^2-(2a-b)^2$

$=(7a-2a-b)(7a+2a-b)$

$=(5a-b)(9a-b)$

$(a+1)^2-(a-1)^2$

$=(a+1-a+1)(a+1+a-1)$

$=4a$

$(x+5)^2-x^2$

$=(x+5-x)(x+5+x)$

$=5(2x+5)$

$(x+2)^2-9x^2$

$=(x+2)^2-(3x)^2$

$=(x+2-3x)(x+2+3x)$

$(7x-4)^2-(2x+1)^2$

$=[74-4-(2x+1)](7x-4+2x+1)$

$=(5x-5)(9x-3)$

$(3x+1)^2-(5x-1)^2$

$=(3x+1-5x+1)(3x+1+5x-1)$

$=(-2x+2).8x$

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