Toán Lớp 8: (2x-3)^2=(4x+3)^2 ai giải hộ mik vs

Question

Toán Lớp 8:  (2x-3)^2=(4x+3)^2 ai giải hộ mik vs

trucoanh55 · Answer

Giải đáp:       Lời giải và giải thích chi tiết:    (2x-3)^2=(4x+3)^2     => ( left[  begin{array}{l}2x-3 =4x+3  2x-3=-(4x+3) end{array}  right. )      => ( left[  begin{array}{l}2x-4x=3+3  2x-3=-4x-3 end{array}  right. )      => ( left[  begin{array}{l}-2x= 6  2x+4x=-3 +3  end{array}  right. )      => ( left[  begin{array}{l}x=6:(-2)  6x=0 end{array}  right. )      => ( left[  begin{array}{l}x=-3  x=0:6 end{array}  right. )      => ( left[  begin{array}{l}x=-3  x=0 end{array}  right. )     vậy x= 0 ; x=-3

lanngocha · Answer

(2x-3)^2=(4x+3)^2   &hArr;(2x-3)^2-(4x+3)^2=0   &hArr;(2x-3-4x-3)(2x-3+4x+3)=0   &hArr;(-2x-6).6x=0   &hArr;-12x(x+3)=0   &hArr; ( left[  begin{array}{l}-12x=0  x+3=0 end{array}  right. )    &hArr; ( left[  begin{array}{l}x=0  x=-3 end{array}  right. )    Vậy x=0 hoặc x=-3