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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: 1.Khai triển 125 – $8x^{3}$ 2.Tìm x a) (4x-1).(2x+3)- $8x^{2}$ = 5 b)16 – $(2x-1)^{2}$

Toán Lớp 8: 1.Khai triển
125 – $8x^{3}$
2.Tìm x
a) (4x-1).(2x+3)- $8x^{2}$ = 5
b)16 – $(2x-1)^{2}$

Comments ( 2 )

  1. #tnvt
    1)
    125-8x^3
    =5^3-(2x)^3
    =(5-2x)(25+10x+4x^2)
    2)
    a)(4x-1)(2x+3)-8x^2=5
    <=>8x^2+12x-2x-3-8x^2=5
    <=>10x=8
    <=>x=4/5
    Vậy x=4/5
    b)16-(2x-1)^2=0
    <=>4^2-(2x-1)^2=0
    <=>(4-2x+1)(4+2x-1)=0
    <=>(5-2x)(3+2x)=0
    <=>[(5-2x=0),(3+2x=0):}
    <=>$\left[\begin{matrix} x=\dfrac{5}{2} \\ x=\dfrac{-3}{2} \end{matrix}\right.$
    Vậy x\in{5/2;-3/2}

  2. Đáp án:
     
    Giải thích các bước giải:
     

    toan-lop-8-1-khai-trien-125-8-3-2-tim-a-4-1-2-3-8-2-5-b-16-2-1-2

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222-9+11+12:2*14+14 = ? ( )