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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: 1 14x^2y-21xy^2+28x^2y^2 2 x^2-6x+5 3 8x^3+12x^2+6x+1 4 3x-(x-7)+8.(x-7) 5 x^2-2xy+y^2-4 6 (x-5)^2-1 7 x^3-2xy+y^2-x+y 8 x^2-2xy+y

Toán Lớp 8: 1 14x^2y-21xy^2+28x^2y^2
2 x^2-6x+5
3 8x^3+12x^2+6x+1
4 3x-(x-7)+8.(x-7)
5 x^2-2xy+y^2-4
6 (x-5)^2-1
7 x^3-2xy+y^2-x+y
8 x^2-2xy+y^2-x+y
9 a^3+3a^2+1a +12
phân tích đa thức thành nhân tử

Comments ( 1 )

  1. ~ gửi bạn ~
    Giải đáp:
    … 
    Lời giải và giải thích chi tiết:
    1) 14x^2y – 21xy^2 + 28x^2y^2
    =  7xy.(2x – 3y + 4xy)
    —-
    2) x^2 – 6x + 5
    = x^2 – x – 5x + 5
    = x.(x – 1) – 5.(x – 1)
    = (x – 1).(x – 5)
    —-
    3) 8x^3+12x^2+6x+1
    = (2x)^3 + 3.(2x)^2.1 + 3.2x + 1
    = (2x + 1)^3
    —-
    4) 3x.(x – 7) + 8.(x – 7)
    = (x – 7).(3x + 8)
    —-
    5) x^2 – 2xy + y^2 – 4
    = (x^2 – 2xy + y^2) – 4
    = (x – y)^2 – 2^2
    = (x – y – 2).(x – y + 2)
    —-
    6) (x – 5)^2 – 1
    = (x – 5)^2 – 1^2
    = (x – 5 – 1).(x – 5 + 1)
    = (x – 6).(x – 4)
    —-
    7) x^2 – 2xy + y^2 – x + y ( sửa đề: x^3 -> x^2 )
    = (x^2 – 2xy + y^2) – (x – y)
    = (x – y)^2 – (x – y)
    = (x – y).(x – y -1)
    —-
    8) giống 7)
    —-
    9) a^3 + 3a^2 + 4a + 12 ( sửa đề: a -> 4a )
    = (a^3+3a^2)+(4a+12)
    = a^2.(a+3)+4.(a+3)
    = (a + 3).(a^2 + 4)

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222-9+11+12:2*14+14 = ? ( )

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