Toán Lớp 7: Tính:b)9/10:1 bốn phần 5-(-0,5) mũ 2-|1/2-1|mũ3 ;b(1-2/3)mũ2 -2 phần1/3:(-14)-|1/6-1|
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Toán Lớp 7: Tính:b)9/10:1 bốn phần 5-(-0,5) mũ 2-|1/2-1|mũ3 ;b(1-2/3)mũ2 -2 phần1/3:(-14)-|1/6-1|
Comments ( 1 )
b)\dfrac{9}{{10}}:1\dfrac{4}{5} – {\left( { – 0,5} \right)^2} – {\left| {\dfrac{1}{2} – 1} \right|^3}\\
= \dfrac{9}{{10}}:\dfrac{9}{5} – {\left( {\dfrac{{ – 1}}{2}} \right)^2} – {\left| { – \dfrac{1}{2}} \right|^3}\\
= \dfrac{9}{{10}}.\dfrac{5}{9} – \dfrac{1}{4} – \dfrac{1}{8}\\
= \dfrac{1}{2} – \dfrac{1}{4} – \dfrac{1}{8}\\
= \dfrac{1}{8}\\
b){\left( {1 – \dfrac{2}{3}} \right)^2} – 2\dfrac{1}{3}:\left( { – 14} \right) – \left| {\dfrac{1}{6} – 1} \right|\\
= {\left( {\dfrac{1}{3}} \right)^2} – \dfrac{7}{3}.\dfrac{1}{{ – 14}} – \left| {\dfrac{{ – 5}}{6}} \right|\\
= \dfrac{1}{9} + \dfrac{1}{6} – \dfrac{5}{6}\\
= \dfrac{1}{9} – \dfrac{2}{3}\\
= \dfrac{{ – 5}}{9}
\end{array}$