Toán Lớp 7: Tìm x,y biết :
$\frac{x}{4}$ =$\frac{2y+1}{3}$ =$\frac{x-2y-1}{y}$(với y≠0)
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Toán Lớp 7: Tìm x,y biết :
$\frac{x}{4}$ =$\frac{2y+1}{3}$ =$\frac{x-2y-1}{y}$(với y≠0)
Comments ( 2 )
$ x−2y−1/y=x/4=2y+1/3=x−2y−1/4−3=x−2y−1/1 $
$ ⇒ $ \(\left[ \begin{array}{l}y=1\\x−2y−1=0\end{array} \right.\)
$ ⇒ $ \(\left[ \begin{array}{l}x/4=2y+1/3=3/3=1⇒x=4⇒(x;y)=(1;4)\\x/4=2y+1/3=0/y=0⇒x=0 ⇒(x;y)=(0;-1/2) \end{array} \right.\)
chúc bn học tốt
cho mk 5* + ctlhn nhé