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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: tìm x : $\frac{3}{2}$ < x < 2,5 - $\frac{1}{2}$ + $\frac{3}{4}$

Home/ Toán Lớp 7: tìm x : $\frac{3}{2}$ < x < 2,5 - $\frac{1}{2}$ + $\frac{3}{4}$

Toán Lớp 7: tìm x : $\frac{3}{2}$ < x < 2,5 - $\frac{1}{2}$ + $\frac{3}{4}$

Tháng Bảy 24, 2022 Toán học 2 Comments 0 views

Toán Lớp 7: tìm x :
$\frac{3}{2}$ < x < 2,5 - $\frac{1}{2}$ + $\frac{3}{4}$

Comments ( 2 )

  1. mocmien87
    mocmien87
    24 Tháng Bảy, 2022 at 4:03 chiều
    Reply
    2,5-$\dfrac{1}{2}$+$\dfrac{3}{4}$=$\dfrac{10}{4}$-$\dfrac{2}{4}$+$\dfrac{3}{4}$=$\dfrac{10-2+3}{4}$=$\dfrac{11}{4}$ 
    Vậy $\dfrac{3}{2}$<x<$\dfrac{11}{4}$
    => $\dfrac{6}{4}$<x<$\dfrac{11}{4}$
    => x={$\dfrac{7}{4}$;$\dfrac{8}{4}$;$\dfrac{9}{4}$;$\dfrac{10}{4}$}

  2. buianhtuan
    buianhtuan
    24 Tháng Bảy, 2022 at 4:03 chiều
    Reply
    3/2<x<2,5- 1/2 + 3/4
    3/2<x<11/4
    6/4<(x.4)/4<11/4
    =>6<4x<11
    =>x=2
    Vậy :x=2

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222-9+11+12:2*14+14 = ? ( )

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