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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: tìm x: ` ( |x| – 3/2 ) . ( 2x^2 – 10 ) = 0 `

Toán Lớp 7: tìm x:
( |x| – 3/2 ) . ( 2x^2 – 10 ) = 0

Comments ( 2 )

  1. ~ Bạn tham khảo ~
    (|x|-3/2) (2x^2 – 10) = 0
    Trường hợp 1:
    |x|-3/2 =0
    => |x|-3/2= 0
    => |x| = 3/2
    => x = 3/2 hoặc x = -3/2
    Trường hợp 2 :
    2x^2 – 10 = 0
    => 2x^2 = 10
    => x^2 = 5
    => x = ∅
    Vậy x in {3/2 ; -3/2}
    $#Vịt vàng$

  2. Answer
    (|x| – 3/2) . (2x^{2} – 10) = 0
    => $\left[\begin{matrix} |x|-\dfrac{3}{2}=0\\ 2x^{2}-10=0\end{matrix}\right.$
    => $\left[\begin{matrix} |x|=0+\dfrac{3}{2}\\ 2x^{2}=0+10\end{matrix}\right.$
    => $\left[\begin{matrix} |x|=\dfrac{3}{2}\\ 2x^{2}=10\end{matrix}\right.$
    => $\left[\begin{matrix} x=\pm\dfrac{3}{2}\\ x^{2}=10:2\end{matrix}\right.$
    => $\left[\begin{matrix} x=\pm\dfrac{3}{2}\\ x^{2}=5(loại)\end{matrix}\right.$
    $\text{Vậy}$ x \in {3/2 ; -3/2}

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222-9+11+12:2*14+14 = ? ( )

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