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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: Tìm x 27 : ( x – $\frac{3}{2}$ ) = ( x – $\frac{3}{2} $)^3 : 3

Toán Lớp 7: Tìm x
27 : ( x – $\frac{3}{2}$ ) = ( x – $\frac{3}{2} $)^3 : 3

Comments ( 1 )

  1. Giải đáp:
    \(\left[ \begin{array}{l}
    x = \dfrac{9}{2}\\
    x =  – \dfrac{3}{2}
    \end{array} \right.\)
    Lời giải và giải thích chi tiết:
    \(\begin{array}{l}
    DK:x \ne \dfrac{3}{2}\\
    27:\left( {x – \dfrac{3}{2}} \right) = {\left( {x – \dfrac{3}{2}} \right)^3}:3\\
     \to \dfrac{{27}}{{x – \dfrac{3}{2}}} = \dfrac{{{{\left( {x – \dfrac{3}{2}} \right)}^3}}}{3}\\
     \to {\left( {x – \dfrac{3}{2}} \right)^4} = 27.3\\
     \to {\left( {x – \dfrac{3}{2}} \right)^4} = {3^3}.3\\
     \to {\left( {x – \dfrac{3}{2}} \right)^4} = {3^4}\\
    \end{array}\)
    \(\begin{array}{l}
     \to \left[ \begin{array}{l}
    x – \dfrac{3}{2} = 3\\
    x – \dfrac{3}{2} =  – 3
    \end{array} \right.\\
     \to \left[ \begin{array}{l}
    x = \dfrac{9}{2}\\
    x =  – \dfrac{3}{2}
    \end{array} \right.
    \end{array}\)

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222-9+11+12:2*14+14 = ? ( )