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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: Tìm x: 1, ║x-3 ║=2x-5 ║n ║là giá trị tuyệt đối nha

Toán Lớp 7: Tìm x:
1, ║x-3 ║=2x-5
║n ║là giá trị tuyệt đối nha

Comments ( 2 )

  1. | x – 3| = 2x – 5
    => \(\left[ \begin{array}{l}2x – 5 = x – 3\\2x – 5 = -x + 3\end{array} \right.\) 
    =>\(\left[ \begin{array}{l}2x – 5 – x = -3\\2x + x – 5 = 3\end{array} \right.\) 
    =>\(\left[ \begin{array}{l}x – 5=-3\\3x – 5 = 3\end{array} \right.\) 
    =>\(\left[ \begin{array}{l}x =2\\3x = 8\end{array} \right.\)
    =>\(\left[ \begin{array}{l}x=2\\x=8/3\end{array} \right.\) 
    Vậy x ∈ { 2 ; 8/3 }

  2. Giải đáp:
     $\left \{ {{2x-5≥0} \atop {\left[ \begin{array}{l}x-3=2x-5\\x-3=-(2x-5)\end{array} \right.}} \right.$⇔$\left \{ {{2x≥5} \atop {\left[ \begin{array}{l}x-2x=-5+3\\x+2x=5+3\end{array} \right.}} \right.$⇔$\left \{ {{x≥5/2} \atop {\left[ \begin{array}{l}-1x=-2\\3x=8\end{array} \right.}} \right.$ ⇔$\left \{ {{x≥5/2} \atop {\left[ \begin{array}{l}x=2(loại)\\x=8/3\end{array} \right.}} \right.$ 
    Vậy x=8/3
    Chúc bạn HT~

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222-9+11+12:2*14+14 = ? ( )

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