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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: `\text{Tìm x,y} :(x.y)/(2.5) \text{biết} x.y=10 `

Toán Lớp 7: \text{Tìm x,y} :(x.y)/(2.5) \text{biết} x.y=10

Comments ( 2 )

  1. #huy
    (x.y)/(2.5)=x/2=y/5
    (x/2)^2=x/2 . x/2=x/2 . y/5=(x.y)/(2.5)=10/10=1
    <=>(x/2)^2=1^2<=>\(\left[ \begin{array}{l}\dfrac{x}{2}=1\\\dfrac{x}{2}=-1\end{array} \right.\) <=>\(\left[ \begin{array}{l}x=2\\x=-2\end{array} \right.\) 
     Voiws x=2 thay x.y=10
    2.y=10
    y=10:2=5
    Với x=-2 thay x.y=10
    -2.y=10
    y=10:(-2)=-5
    Vậy x=2 thì y=5
    x=-2 thì y=-5

  2. Ta có : x.y = 10
    => (x.y)/(2.5) = 10/10 = 1
    => x/2 . y.5 = 1
    => x/2 = ±1
    <=> x = ±2
    => y/5 = ±5
    <=> y = ±5
     

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222-9+11+12:2*14+14 = ? ( )

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