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Toán Lớp 7: $\frac{2}{(x+3)(x+5)}$+$\frac{5}{(x+5)(x+210)}$ +$\frac{10}{(x+10)(x+20)}$ =$\frac{x}{(x+3)(x+20)}$

Home/ Toán Lớp 7: $\frac{2}{(x+3)(x+5)}$+$\frac{5}{(x+5)(x+210)}$ +$\frac{10}{(x+10)(x+20)}$ =$\frac{x}{(x+3)(x+20)}$

Toán Lớp 7: $\frac{2}{(x+3)(x+5)}$+$\frac{5}{(x+5)(x+210)}$ +$\frac{10}{(x+10)(x+20)}$ =$\frac{x}{(x+3)(x+20)}$

Nhân Tháng Hai 20, 2022 Toán học 2 Comments 0 views

Toán Lớp 7: $\frac{2}{(x+3)(x+5)}$+$\frac{5}{(x+5)(x+210)}$ +$\frac{10}{(x+10)(x+20)}$ =$\frac{x}{(x+3)(x+20)}$

Comments ( 2 )

maianhnhiquynh
20 Tháng Hai, 2022 at 9:59 sáng

Reply

Giải đáp:

2/((x+3)(x+5))+5/((x+5)(x+10))+10/((x+10)(x+20))=x/((x+3)(x+20))

⇔ 1/(x+3)-1/(x+5)+1/(x+5)-1/(x+10)+1/(x+10)-1/(x+20)= x/((x+3)(x+20))

⇔ 1/(x+3)-1/(x+20)=x/((x+3)(x+20))

⇔ 17/((x+3)(x+20))=x/((x+3)(x+20))
->x=17
huyenmi76
20 Tháng Hai, 2022 at 9:59 sáng

Reply

Giải đáp + Lời giải và giải thích chi tiết:

2/((x+3)(x+5))+5/((x+5)(x+10))+10/((x+10)(x+20))=x/((x+3)(x+20))

=>1/(x+3)-1/(x+5)+1/(x+5)-1/(x+10)+1/(x+10)-1/(x+20)=x/((x+3)(x+20))

=>1/(x+3)-1/(x+20)=x/((x+3)(x+20))

=>(x+20)/((x+3)(x+20))-(x+3)/((x+20)(x+3))=x/((x+3)(x+20))

=>(x+20-x-3)/((x+3)(x+20))=x/((x+3)(x+20))

=>x=x+20-x-3

=>x=17

vậy x=17

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