Toán Lớp 7: $\frac{2x-1}{x +3}$ = $\frac{-3}{4}$
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Toán Lớp 7: $\frac{2x-1}{x +3}$ = $\frac{-3}{4}$
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Answer
{2x – 1}/{x + 3} = {-3}/4
=> 4 . (2x – 1) = -3 . (x + 3)
=> 8x – 4 = -3x – 9
=> 8x + 3x = -9 + 4
=> 11x = -5
=> x = -5 : 11
=> x = -5/11
Vậy x = -5/11
$#QLinkVN$
Giải phương trình trên như sau:
(2x+1)/(x+3)=(-3)/(4)
⇔4.(2x-1)=(-3).(x+3)
⇔8x-4=-3x-9
⇔8x+3x=-9+4
⇔11x=-5
⇔x=(-5)/(11)
Vậy x=(-5)/(11)