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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: Cho a,b,c khác 0 thoả mãn: 12ab+1/4b=4bc+1/c=3ac+1/3a. cmr: 3a=4b=c

Toán Lớp 7: Cho a,b,c khác 0 thoả mãn: 12ab+1/4b=4bc+1/c=3ac+1/3a. cmr: 3a=4b=c

Comments ( 1 )

  1. $\\$
    giả sử 3a=4b=c
    => (3a)/12=(4b)/12=c/12
    => a/4=b/3=c/12
    Đặt a/4=b/3=c/12=k(k\ne0)
    => a=4k, b=3k, c=12k
    (12ab+1)/(4b)
    =(12 . 4k . 3k+1)/(4.3k)
    =(144k^2 +1)/(12k)
    (4bc+1)/c
    = (4.3k.12k+1)/(12k)
    =(144k^2+1)/(12k)
    (3ac+1)/(3a)
    =(3.4k.12k+1)/(3a)
    = (144k^2+1)/(3.4k)
    = (144k^2+1)/(12k)
    Do đó : (12ab+1)/(4b)=(4bc+1)/c=(3ac+1)/(3a)
    Thật vậy nếu (12ab+1)/(4b)=(4bc+1)/c=(3ac+1)/(3a) thì 3a=4b=c
     

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222-9+11+12:2*14+14 = ? ( )