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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: ( a -b -c ) ^2 = a^2 + b^2 + c^2 -2ab + 2bc – 2ac hay ( a-b-c ) ^2 = a^2 – b^2 – c^2 -2ab +2bc -2ac . Cọn 1 trong 2 cái nha , giả thíc

Toán Lớp 7: ( a -b -c ) ^2 = a^2 + b^2 + c^2 -2ab + 2bc – 2ac
hay ( a-b-c ) ^2 = a^2 – b^2 – c^2 -2ab +2bc -2ac .
Cọn 1 trong 2 cái nha , giả thích cho mk nữa

Comments ( 2 )

  1. Đáp án:
     
    Giải thích các bước giải:
     

    toan-lop-7-a-b-c-2-a-2-b-2-c-2-2ab-2bc-2ac-hay-a-b-c-2-a-2-b-2-c-2-2ab-2bc-2ac-con-1-trong-2-cai

  2. (a-b-c)^2
    = (a-b-c)(a-b-c)
    =a(a-b-c) – b(a-b-c) – c(a-b-c)
    = a^2 -ab – ac – ab + b^2 + bc – ca + bc + c^2
    =a^2 – (ab + ab) – (ac + ac) + b^2 + c^2 + (bc + bc)
    = a^2 – 2ab – 2ac + 2bc + b^2 + c^2
     

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222-9+11+12:2*14+14 = ? ( )