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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: a.2/5 – 1 2/3 = √4/9 b.1/5 – l1/5 – xl = 1/5 c. l5- 3xl + 2/3=1/6

Toán Lớp 7: a.2/5 – 1 2/3 = √4/9
b.1/5 – l1/5 – xl = 1/5
c. l5- 3xl + 2/3=1/6

Comments ( 2 )

  1. Giải đáp:
     
    Lời giải và giải thích chi tiết:
     a, 2/5 – 12/3 x = √4/9
    => 12/3 x = 2/5 – 2/3
    => 12/3 x = -4/15
    => x = -4/15 . 3/12
    => x = -1/15.
    Vậy x = -1/15.
    b, 1/5 – ║1/5 – x║ = 1/5
    => ║1/5 – x║ = 0
    => 1/5 – x = 0
    => x = 1/5
    Vậy x = 1/5
    c, ║5-3x║ + 2/3 = 1/6
    => ║5-3x║ = 1/6 – 4/6
    => ║5-3x║ = -1/2
    mà ║x║ ≥ 0
    Vậy x ∈ ∅

  2. \text{a)} 2/5 – 1 2/3 xx x = \sqrt{4/9}
    => 2/5 – 5/3 xx x = \sqrt{4}/\sqrt{9}
    => 2/5 – 5/3 xx x = 2/3
    => 5/3 xx x = 2/5 – 2/3
    => 5/3 xx x = (-4)/15
    => x = (-4)/15 : 5/3
    => x = (-4)/15 : 5/3
    => x = (-4)/25
    \text{Vậy,} x = (-4)/25
    —————–
    \text{b)} 1/5 – |1/5 – x| = 1/5
    => |1/5 – x| = 1/5 – 1/5
    => |1/5 – x| = 0
    => 1/5 – x = 0
          x = 1/5 – 0
          x = 1/5
    \text{Vậy,} x = 1/5
    —————–
    \text{c)} |5 – 3x| + 2/3 = 1/6
    => |5 – 3x| = 1/6 – 2/3
    => |5 – 3x| = (-1)/2
    => \(\left[ \begin{array}{l}5 – 3x = \dfrac{-1}{2}\\-(5 – 3x) = \dfrac{-1}{2}\end{array} \right.\)
    => \(\left[ \begin{array}{l}5 – 3x = \dfrac{-1}{2}\\5 – 3x = \dfrac{1}{2}\end{array} \right.\)
    => \(\left[ \begin{array}{l}3x = 5 – \dfrac{-1}{2}\\3x = 5 – \dfrac{1}{2}\end{array} \right.\)
    => \(\left[ \begin{array}{l}3x = \dfrac{11}{2}\\3x = \dfrac{9}{2}\end{array} \right.\)
    => \(\left[ \begin{array}{l}x = \dfrac{11}{2} : 3\\x = \dfrac{9}{2} : 3\end{array} \right.\)
    => \(\left[ \begin{array}{l}x = \dfrac{11}{6}\\x = \dfrac{3}{2}\end{array} \right.\)
    \text{Vậy,} x = 11/6 \text{ hoặc } 3/2

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222-9+11+12:2*14+14 = ? ( )

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