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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: ( x – 3,5 ) ² + ( y – 1/10 ) ² ≤ 0

Tháng Sáu 15, 2022 Toán học 2 Comments 0 views

Toán Lớp 7: ( x – 3,5 ) ² + ( y – 1/10 ) ² ≤ 0

Comments ( 2 )

  1. quynhthanhnhu
    quynhthanhnhu
    15 Tháng Sáu, 2022 at 3:02 chiều
    Reply
    Answer
    $\text{Ta có:}$
    (x – 3,5)^{2} \ge 0 AA x \in QQ
    (y – 1/10)^{2} \ge 0 AA y \in QQ
    => (x – 3,5)^{2} + (y – 1/10)^{2} \ge 0 AA x,y \in QQ
    => (x – 3,5)^{2} + (y – 1/10)^{2} = 0
    => {(x – 3,5 = 0),(y – 1/10 = 0):}
    => {(x= 0+3/5),(y= 0+1/10):}
    => {(x=3/5),(y= 1/10):}
    $\text{Vậy}$ (x , y) = (3/5 , 1/10)

  2. diepbich93
    diepbich93
    15 Tháng Sáu, 2022 at 3:01 chiều
    Reply
     ( x – 3,5 )^2 + ( y – 1/10 )^2 ≤ 0
    Ta có : ( x – 3,5 )^2 ≥ 0 , ( y – 1/10 )^2 ≥0
    Nhưng theo đề bài , ta có : ( x – 3,5 )^2 + ( y – 1/10 )^2 ≤ 0
    Do đó :  ( x – 3,5 )^2 + ( y – 1/10 )^2 = 0
    => $\left \{ {{(x-3,5)^2=0} \atop {(y-1/10)^2 = 0}} \right.$
    => $ \left \{ {{x-3,5=0} \atop {y-1/10=0}} \right.$
    => $\left \{ {{x=3,5} \atop {y=1/10}} \right.$
     

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222-9+11+12:2*14+14 = ? ( )

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