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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: (2x – 3)$^{2}$ = 16 /==-

Toán Lớp 7: (2x – 3)$^{2}$ = 16
/……………………….

Comments ( 2 )

  1. Giải đáp + Lời giải và giải thích chi tiết:
    (2x-3)^{2}=16=(+-4)^{2}
    => \(\left[ \begin{array}{l}2x-3=4\\2x-3=-4\end{array} \right.\) 
    => \(\left[ \begin{array}{l}2x=7\\2x=-1\end{array} \right.\) 
    => \(\left[ \begin{array}{l}x=\dfrac{7}{2}\\x=-\dfrac{1}{2}\end{array} \right.\) 
     

  2. Lời giải chi tiết:
    (2x-3)^2=16
    =>\(\left[ \begin{array}{l}(2x-3)^2=4^2\\(2x-3)^2=(-4)^2\end{array} \right.\)
    =>\(\left[ \begin{array}{l}2x-3=4\\2x-3=-4\end{array} \right.\)
    =>\(\left[ \begin{array}{l}2x=7\\2x=-1\end{array} \right.\)
    =>\(\left[ \begin{array}{l}x=\dfrac{7}{2}\\x=-\dfrac{1}{2}\end{array} \right.\)
    Vậy x∈{7/2;-1/2}

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222-9+11+12:2*14+14 = ? ( )