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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: Tính 2A=1/1.3+1/3.5+ …+1/99.101

Toán Lớp 6: Tính
2A=1/1.3+1/3.5+ …+1/99.101

Comments ( 2 )

  1. Giải đáp:
    $\\$
    2A = 1/(1×3) + 1/(3×5) + … + 1/(99×101)
    ⇔ 2A = 1/2 × [1 – 1/3 + 1/3 – 1/5 + … + 1/99 – 1/101]
    ⇔ 2A = 1/2 × [1 + (-1/3 + 1/3) + … + (-1/99 + 1/99) – 1/101]
    ⇔ 2A = 1/2 × [1 – 1/101]
    ⇔ 2A = 1/2 × [101/101 – 1/101]
    ⇔ 2A = 1/2 × 100/101
    ⇔ 2A = 50/101
    ⇔ A = 50/101 ÷ 2
    ⇔ A = 50/101 × 1/2
    ⇔ A = 25/101
    Vậy A=25/101
     

  2. Giải đáp:
    A=25/101
    Lời giải và giải thích chi tiết:
    2A=1/1.3+1/3.5+ …+1/99.101
    2A=(1.2/1.3+1.2/3.5+ …+1.2/99.101):2
    2A=(2/1.3+2/3.5+ …+2/99.101). 1/2
    2A=(1-1/3+1/3-1/5+…+1/99-1/101). 1/2
    2A=(1-1/101). 1/2
    2A=(101/101-1/101). 1/2
    2A=100/101. 1/2
    A=100/101. 1/2. 1/2
    A=100/101. 1/4
    A=100/101.4
    A=[25.\cancel{4}]/[101.\cancel{4}]
    A=25/101
    Vậy A=25/101

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222-9+11+12:2*14+14 = ? ( )

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